The point `P` of a string is pulled up with an acceleration `g`. Then the acceleration of the hanging disc (w.r.t ground) over which the string is wrapped, is

Find the acceleration of C w.r.t. ground.

If block A is moving with an acceleration of 5ms^(-2) , the acceleration of B w.r.t. ground is

If block A is moving with an acceleration of 5ms^(-2) , the acceleration of B w.r.t. ground is

If block A is moving with an acceleration of 5ms^(-2) , the acceleration of B w.r.t. ground is

A body of mass M is hanging by an inextensible string of mass m. If the free end of the string accelerates up with constant acceleration a. find the variation of tension in the string a function of the distance measured from the mass M (bottom of the string).

A body of mass M is hanging by an inextensible string of mass m. If the free end of the string accelerates up with constant acceleration a. find the variation of tension in the string a fuction of the distance measured from the mass M (bottom of the string).

One end of a string of length L is tied to the ceiling of a lift accelerating upwards with an acceleration 2g. The other end o the string is free. The linear mass density of the string varies linearly from 0 to lamda from bottom to top. The acceleration of a wave pulled through out the string is (pg)/(4) . Find p.

One end of a string of length L is tied to the ceiling of a lift accelerating upwards with an acceleration 2. The other end o the string is freee. The linear mass density of the string varies linearly from 0 to lamda from bottom to top. The acceleration of a wave pulled through out the string is (pg)/(4) . Find p.

A pendulum bob is hanging from the roof of an elevator with the help of a light string. When the elevator moves up with uniform acceleration 'a' the tension in the string is T_(1) . When the elevator moves down with the same acceleration, the tension in the string is T_(2) . If the elevator were stationary, the tension in the string would be