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sin[(pi)/(2)-sin^(-1)(-1)/(2)]...

sin[(pi)/(2)-sin^(-1)(-1)/(2)]

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sin [(pi)/(3) - sin^(-1) (-(1)/(2))] is equal to :

sin {(pi)/(3) - sin^(-1) ((-1)/(2)) }=…….

Find the value of sin[pi/3 - sin^(-1) (- 1/2)]

Find the values of the following: sin((pi)/3-Sin^(-1)((-1)/2))

sin(pi/6-sin^(-1)(-1/2))=?

The value of sin((pi)/(2)+2sin^(-1)(1)) is: