A solid sphere of mass `m &` rdius `R` is divided in two parts of `m` mass `(7m)/(8) & (m)/(8)`, and converted to a disc of radius `2R &` solid sphere of radius `'r'` respectively. Find `(I_(1))/(I_(2))` , If `I_(1) & I_(2)` are moment of inertia of disc `&` solid sphere respectively

Moment of inertia of solid sphere of radius r_(0) is

A solid sphere of mass M and radius R is divided into two unequal parts. The first part has a mass of (7M)/(8) and is converted into a uniform disc of radius 2R. The second part is converted into a uniform solid sphere. Let I_(1) be the moment of inertia of the disc about its axis and I_(2) be the moment of inertia of the new sphere about its axis. The ratio (I_(1))/(I_(2)) is equal to __________ .

A solid sphere of mass M and radius R is divided into two unequal parts. The first parts has a mass of (7M)/8 and is converted into a uniform disc of radius 2R. The second part is converted into a uniform solid sphere. Let I_(1) be the moment of inertia of the uniform disc about its axis and I_(2) be the moment of inertia of the sphere made from remaining part about its axis. The ratio I_(1)//I_(2) is 140/x . Find the value of x.

The M.I. of solid sphere of mass M and radius R about its diameter is

The M.I. of solid sphere of mass M and radius R about its diameter is

If the M.I. about diameter, for ring, disc, solid sphere and spherical shell of same radius and mass respectively be I_(1), I_(2), I_(3) and I_(4) , then:

The moment of inertia of a solid sphere of mass M and radius R about the tangent is