" If "f:[1,oo)rarr[0,oo)" is given by "f(x)=x-(1)/(x)," then "f^(-1)(x)=

If f:[1, oo)rarr[2, oo) is given by f(x)=x+(1)/(x) then f^(-1)(x)=

If f : [1, oo) rarr [2, oo) is given by f(x) = x + (1)/(x) then f^(-1) (x) equals:

If f:[1,oo)to[1,oo) is given by f(x)=x+(1)/(x) , then f^(-1)(x) equals :

If f:[1,oo)to[2,oo) is given by f(x)=x+(1)/(x) , then f^(-1)(x) equals :

If f: [1, oo) rarr [5, oo) is given by f(x) = 3x + (2)/(x) , then f^(-1) (x) =

If f[1, oo)rarr[1, oo) is defined by f(x)=2^(x(x-1)) then f^(-1)(x)=

A function f:(0,oo)rarr[0,oo] is given by f(x)=|1-(1)/(x)|, then f(x) is (A) Injective but not surjective (B) Injective and bijective (C) Injective only (D) Surjective only

If f:[1, oo) rarr [2, oo) is defined by f(x)=x+1/x , find f^(-1)(x)

If F :[1,oo)->[2,oo) is given by f(x)=x+1/x ,t h e n \ f^(-1)(x) equals \ \