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A vertical electric field of magnitude 4...

A vertical electric field of magnitude `4.00xx 10^5 NC^(-1)`. just prevents a water droplet of mass `1.000x 10^(-4)b kg`from. falling., find the charge on the droplet.

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A vertical electric field of magnitude 4.00xx 10^5 NC^(-1) . just prevents a water droplet of mass 1.000xx10^(-4) kg from. falling., find the charge on the droplet.

A vertical electric field of magnitude 4.00xx 10^5 NC^(-1) . just prevents a water droplet of mass 1.000xx10^(-4) kg from. falling., find the charge on the droplet.

A Charged particle of mass 1.0 g is suspended through a . silk thread of length 40 cm in a horizantal electric field . of 4.0 xx 10 ^4 NC ^(-1) . If the particle stays aty a distance of . 24 cm from the wall in equilibrium, find the charge on . the particle.

A Charged particle of mass 1.0 g is suspended through a . silk thread of length 40 cm in a horizantal electric field . of 4.0 xx 10 ^4 NC ^(-1) . If the particle stays aty a distance of . 24 cm from the wall in equilibrium, find the charge on . the particle.

A Charged particle of mass 1.0 g is suspended through a silk thread of length 40 cm in a horizantal electric field of 4.0 xx 10 ^4 NC ^(-1) . If the particle stays aty a distance of 24 cm from the wall in equilibrium, find the charge on the particle.

An uniform electric field of magnitude 5 xx 10^(4) NC^(-1) has a dipole of dipole moment 4xx 10^(-9) cm aligned at 30^(@) with the direction of field. Calculate the magnitude of torque acting on the dipole:

Calculate the electric field held strength required to just support a water drop of mass 10^(-7) kg and having a charge of 1.6 xx 10 ^(-19) C .

An electron falls freely in electric field of 9.1 xx 10^3 NC^(-1) , then acceleration of electron is .......

An electron falls through a distance of 2 cm ir a uniform electric field of magnitude 6.0 xx 10^4 NC^(-1) figure (a). The direction of the field is reversed keeping its magnitude unchanged and a proton falls through the same distance figure (b). Compute the time of fall ir each case. Contrast the situation with that oi 'free fall under gravity'. m_(e) = 9.1 xx 10^(-31)kg, m_(p) = 1.7 xx 10^(-27) kg and e = 1.6 xx 10^(-19) C