Find the electric field at a point P on the perpendicular bisector of a uniformly charged rod. The lengthof the rod is L, the charge on it is Q and the distance of P from the centre of the rod is a.

Find the electric field at a point P on the perpendicular bisector of a uniformly charged rod. The length of the rod is L, the charge on it is Q and the distance of P from the centre of the rod is a.

Find the electric field at point P (as shown in figure) on the perpendicular bisector of a uniformly charged thin wire of length L carrying a charge Q. The distance of the point P from the centre of the rod is a =sqrt3/2L .

Find : (i)Electric field intensity due to an infinitely long uniformly charged, straight conductor , at a perpendicular distance d from rod. (ii)Electric field intensity at a point on perpendicular bisector of uniformly charged rod of length l and charge Q at a distance d from the centre of rod.

Calculate the potential at a point on the perpendicular bisector of uniformly charged thin rod (linear density of charge = lambda ) of length 2l at a distance a from the centre of the rod.

The electric field at a point P which is at a distance l on the perpendicular bisector of a uniformly charged wire of length 1 , charge Q=(Q)/(2 pi varepsilon_(0)l^(2)sqrt(k)) where k = ?

Find the electric field and potential at the centre of curvature of a uniformly charged semicircular rod of radius R with a total charge Q in SI. lambda is the linear charge density.

What is the electric field intensity at any point on the axis of a charged rod of length 'L' and linear charge density lambda ? The point is separated from the nearer end by a.

What is the electric field intensity at any point on the axis of a charged rod of length 'L' and linear charge density lambda ? The point is separated from the nearer end by a.

Calculate the potential due to a thin uniformly charged rod of length L at the poiot P shown in figure. The lioear charge density of the rod is lambda C//m