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" The value of the Zener current "...

" The value of the Zener current "

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The following questions consists of two statements.Assertion: Zener diode works as a voltage regulator Reason: Zener voltage is independent of the Zener current variations and change of load resistance.Write the correct response from the following.

The maximum and minimum values of zener diode current are

A 5.0 V stabilized power supply is required to be designed using a 12V DC power supply as an input source. The maximum power rating P_z of the Zener diode is 2.0 W. Using the Zener regulator circuit, calculate: The Zener current Iz at full load.

A 10 V Zener diode along with a seriers resistance R is connected across a 40V supply. Calculate the minimum value of the resistance, ar required, if the maximum Zener current is 50mA .

A 10V of zener diode is connected in series to a resistance across a power supply of 50 V calculate the minimum value of resistance required such that the zener current is 25 mA

In the figure there is a DC voltage regulator circuit, with a Zener breakdown voltage = 6V.If the unregulated input voltage varies between 10V to 16V,then what is the maximum Zener current?

In the figure there is a DC voltage regulator circuit, with a Zener breakdown voltage = 6V.If the unregulated input voltage varies between 10V to 16V,then what is the maximum Zener current?

In the figure there is a DC voltage regulator circuit, with a Zener breakdown voltage = 6V.If the unregulated input voltage varies between 10V to 16V,then what is the maximum Zener current?

During regulation action of a Zener diode correct statement is :- (a) the current and voltage across the Zener remains fixed. (b) the current through the series resistance (RS) changes. (c) the Zener resistance is constant. (d) the resistance offered by the Zener diode changes.

In a given circuit diagram, a 5 V zener diode along with a series resistance is connected across a 50 V power supply. The minimum value of the resistance required, if the maximum zener current is 90 mA will be ___ Omega .