The de Broglie wavelenght `(lambda)` associated with a photoelectron varies with the frequency `(v)` of the incident radiation as,[`v_(0)` is threshold frequency]:

The de Broglie wavelength (lamda) associated with photoelectron varies with frequency (nu) of the incident raidation as [ nu_(0) = threshold frequency]

Maximum kinetic energy (E_(k)) of a photoelectron varies with the frequency (v) of the incident radiation as

Maximum kinetic energy (E_(k)) of a photoelectron varies with the frequency (v) of the incident radiation as

The kinetic energy (E_(k)) of a photoelectron varies with the frequency (v) of the incident radiation as which of the following graph ?

Frequency of radiation incident on metal surface is called threshold frequency.

The maximu kinetic energy (E_(k)) of the photoelectron varies with frequency (v) of the incident light as shown by the curve:

Derive de Broglie wave equation for material particles. (b) Why does photoelectric emission not take place if the frequency of incident radiation is less than threshold frequency ?

The threshold frequency of a metal is f_(0) . When the light of frequency 2f_(0) is incident on the metal plate, the maximum velocity of electrons is v_(1) . When the frequency of the incident radiation is increased to 5f_(0) , the maximum velocity of electron emitted is v_(2) . Find the ratio of v_(1) to v_(2) .