`6g` of urea ( molecular weight `=60)` was dissolved in `9.9` moles of water. If the vapour pressure of pure water is `P^(@)`, the vapour pressure of solution is `:`

6.0 g of urea (molecular weight=60) was dissolved in 9.9 moles of water. If the vapour pressure of pure water is P^@ , the vapour pressure of solution is :

6.0 g of urea (molecular mass = 60) was dissolved in 9.9 moles of water. If the vapour pressure of pure water is P^(@) , the vapour pressure of solution is :

6.0 g of urea (molecules mass = 60)was dissolved in 9.9 moles of water. If the vspour presssure of pure water is P^(@) , the vapour pressure of solution is :

6.0 g of urea (molecules mass = 60)was dissolved in 9.9 moles of water. If the vspour presssure of pure water is P^(@) , the vapour pressure of solution is :

9 gram anhydrous oxalic acid (mol. wt. = 90) was dissolved in 9.9 moles of water. If vapour pressure of pure water is P_(1)^(@) the vapour pressure of solution is

The vapour pressure of water at T(K) is 20 mm Hg. The following solutions are prepared at T(K) I. 6 g of urea (molecular weight = 60) is dissolved in 178.2 g of water. II. 0.01 mol of glucose is dissolved in 179.82 g of water. III. 5.3 g of Na_(2)CO_(3) (molecular weight = 106) is dissolved in 179.1 g of water. Identify the correct order in which the vapour pressure of solutions increases

The vapour pressure of water at T(K) is 20 mm Hg. The following solutions are prepared at T(K) I. 6 g of urea (molecular weight = 60) is dissolved in 178.2 g of water. II. 0.01 mol of glucose is dissolved in 179.82 g of water. III. 5.3 g of Na_(2)CO_(3) (molecular weight = 106) is dissolved in 179.1 g of water. Identify the correct order in which the vapour pressure of solutions increases

6 g of urea is dissolved in 90g of boiling water. The vapour pressure of the solution is

The weight of urea to be dissolved in 100 g. of water to decrease the vapour pressure of water by 5% is