two resistors R and 2R are connected in series in an electric circuit. The thermal energy developed in R and 2R are in the ratio

Two resistances R and 2R are connected in parallel in an electric circuit. The thermal energy developed in R and 2R are in the ratio

Two resistances R and 2R are connected in parallel in an electric circuit. The thermal energy developed in R and 2R are in the ratio

Two resistances R and 2R are connected in parallel in an electric circuit. The thermal energy developed in R and 2R are in the ratio

Two resistances R and 2R are connected in parallel to an electric current Thermal energy developed in R and 2R are in the ratio :

If two resistors of R_(1) and R_(2) ohms are connected in parallel in an electric circuit to make an R ohm resistor, the value of R can be found from the equation, (1)/(R)=(1)/(R_(1))+(1)/(R_(2)) If R_(1) is decreasing at the rate of 1 ohm/sec and R_(2) i increasing at the rate of 0.5 ohm/sec, at what rate is R changing when R_(1)=75 ohm and R_(2)=50 ohm ?

You take two resistors of resistance 2R and 3R and connect them in parallel in an electric circuit. Calculate the ratio of electric power consumed by 2R and 3R resistors.

Two resistors R and 3 R are connected in series. Ratio of rate of heat dessipated in R to that in 3 R is x_(1) . Similarly when R and 3 R are connected in parallel to each other, ratio of the heat dessipated in R to that in 3 R is x_(2) . What will be the value of x_(2)//x_(1) ?