Find the distance travelled by a body before coming rest, if it is moving with a speed of `10ms^(-1)` and the coefficient of friction between the ground and the body is `0.4`.

A person of mass 72kg sitting on ice pushes a block of mass of 30kg on ice horizontally with a speed of 12ms^(-1) .The coefficient of friction between the man and ice and between block and ice is 0.02 .If g=10ms^(-1) ,the distance between man and the block, when they come to rest is

A person of mass 72 kg sitting on ice pushes a block of mass of 30kg on ice horizontally with a speed of 12 ms^(1) . The coefficient of friction between the man and ice and between block and ice in 0.02. If g =10ms^2 , the distances between man and the block, when they come to rest is

A man of mass 60kg sitting on ice pushes a block of mass 12kg on ice horizontally with a speed of 5ms^(-1) The coefficient of friction between the man and ice and between block and ice is 0.2 If g =10ms^(2) the distance beteen man and the block when they come to rest is .

A body moving on the ground with a velocity of 15m//s comes to rest after covering a distance of 25m If acceleration due to gravity is 10m//s^(2) Calculate the coefficient of friction between the ground and the body .

A body moving on ground with a velocity of 14 m//s comes to rest due to friction after moving ove a distance of 50 m. Detennine the co-efficient of friction between the body and the ground.

A body moving on the surface of the earth at 14 "m.s"^(-1) comes to rest due to friction after covering 50 m. Find the coefficient of friction between the body and the earth's surface. Given, acceleration due to gravity = 9.8 "m.s"^(-2) .

The brakes of a car moving at 20 m/s along a horizontal road are suddenly applied and it comes to rest after travelling some distance if the coefficient of friction between the tyres and the road is 0.90 and it is assumed that all four tyres behave identically, the shortest distance the car would travel before coming to a stop is