If latus rectum of ellipse `x^2/25+y^2/16=1` is double ordinate of parabola `y^2=4ax`, then find the value of a.

The latus rectum of the ellipse 16x^2+y^2=16 is:

The latus rectum of the ellipse x^2/25-y^2/16=1 are same .

The latus rectum of the ellipse 9x^2+16y^2=144 , is:

Find the length of latus rectum of the ellipse x^(2)/25+y^(2)/16=1 .

Find the area of the parabola y^2=4ax and its latus rectum.

Find the latus rectum of ellipse (x^(2))/(36) + (y^(2))/(16) = 1 .

Find the length of latus rectum of the ellipse. x^2/16+y^2/9=1 .

The latus rectum of the parabola y^(2)=5x+4y+1 is

If the line 2x+3y=1 touches the parabola y^(2)=4ax then the length of latus rectum is

Ellipse (x^2)/(a^2)+(y^2)/(b^2)=1,(a > b), If the extremities of the latus rectum of the with positive ordinates lie on the parabola x^(2) = 3(y + 3) , then length of the transverse axis of ellipse is