" f "tan x+tan(x+(pi)/(2))+tan(x+(2 pi)/(3))=3," then prove "t

If tan x+tan(x+(pi)/(3))+tan(x+(2 pi)/(3))=3 then prove that (3tan x-tan^(3)x)/(1-3tan^(2)x)=1

tan x tan((pi)/(3)-x)tan((pi)/(3)+x)=tan3x

If tanx+tan((pi)/(3)-x)+tan((2pi)/(3)+x)=3 , then

tan x*tan(x+(pi)/(3))*tan(x+(2 pi)/(3))=sqrt(3)

If t a n x+tan(x+pi/3)+tan(x+(2pi)/3)=3, then prove that (3tanx-t a n^3x)/(1-3t a n^2x)=1 .

tan x+ tan(x+(pi)/(3))+ tan(x+(2pi)/(3))=3impliestan 3 x=

Period of tan x tan((2 pi)/(3)-x)tan((2 pi)/(3)+x) is

If tanx+tan(x+pi/3)+tan(x+(2pi)/3)=3 then prove that (3tanx-tan^3x)/(1-3tan^2x)=1

The general solution of the equation tan x+tan(x+(pi)/(3))+tan(x+(2 pi)/(3))=3and why canl't we use tan A+tan B+tan C=tan A*tan B.tan C

tan x+tan(x+(pi)/(3))+tan(x+2(pi)/(3))=3 prove that (3tan x-tan^(3)x)/(1-3tan^(2)x)=1