=a(cos theta+theta sin theta)*y=a(sin theta-theta cos theta)

Find (dy)/(dx), when x=a(cos theta+theta sin theta) and y=a(sin theta-theta cos theta)

If x=a(cos theta+theta sin theta) and y=a(sin theta-theta cos theta) and theta increases at uniform rate omega . The velocity of particle is

Consider the curve x=a(cos theta+theta sin theta) and y=a(sin theta-theta cos theta). What is (dy)/(dx) equal to? What is (d^(2)y)/(dx^(2)) equal to?

Show that the normal at any point theta to the curve x=a cos theta+a theta sin theta,y=a sin theta-a theta cos theta is at a constant distance from the origin.

If x = cos theta + theta sin theta, y = sin theta - theta cos theta then (d ^(2) y)/(dx ^(2)) =

If x = a (cos theta + theta sin theta) and y = a (sin theta - theta cos theta) , find (d^2y)/(dx^2) at t = pi/4 .