Among P, Q, R and S the aromatic compound(s) is/are: a) çi A1C1, → P b) NaH Q C) (NH4)2CO3 100-115°C R d) HCI S

Among P, Q, R and S, the aromatic compounds(s) is/are

Among P,Q,R and S , the aromtic compound(s) is /are

Among P, Q, R, S the aromatic compound is

Among P, Q, R, S the aromatic compound is

if P,q, r, s in R such that p r= 2 ( q+ s) then

Rs. 1050 are divided among P, Q and R. The share of P is 2/5 of the combined share of Q and R.P gets R s .200 b. R sdot 300 c. R s .320 d. R s .420

(i) P+C("carbon")+Cl_(2) to Q+CO (ii) Q+H_(2)O to R+HCl (iii) BN+H_(2)O to R+NH_(3) uarr (iv) Q+LiAlH_(4) to S+LiCl+AlCl_(3) (v) S+H_(2) to R+H_(2) uarr (vi) S+NaH to T (P,Q,R,S annd T do not represent their chemical symbols) Q. Compound S is: (I) an odd e^(-) compound (II) (2c-3e^(-)) compound (III) a electron deficient compound (IV) a sp^(2) hybridized compound Choose the correct code:

(i) P+C("carbon")+Cl_(2) to Q+CO uaarr (ii) Q+H_(2)O to R+HCl (iii) BN+H_(2)O to R+NH_(3) uarr (iv) Q+LiAlH_(4) to S+LiCl+AlCl_(3) (v) S+H_(2) to R+H_(2) uarr (vi) S+NaH to T (P,Q,R,S annd T do not represent their chemical symbols) Q. Compound S is: (I) an odd e^(-) compound (II) (2c-3e^(-)) compound (III) a electron deficient compound (IV) a sp^(2) hybridized compound Choose the correct code:

If p + r = 2q and 1/q + 1/s = 2/r , then prove that p : q = r : s .