In Figure, ABD is a triangle right-angled at A and `A C_|_B D`. Show that
(i)`A B^2=B C.B D`
(ii) `A C^2=B C.D C`
(iii) `A D^2=B D.C D`

Explanation

(i) Here, ABD is a triangle right angled at A and `AC ⊥ BD`


`⇒ ΔBAD ∼ ΔBCA`


`⇒ (AB)/(BC) = (BD)/(AB)`
(Corresponding sides of similar triangle)
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