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From any point P tangents of length t(1)...

From any point P tangents of length `t_(1)` and `t_(2)` are drawn to two circles with centre `A,B` and if `PN` is the perpendicular from `P` to the radical axis and `t_(1)^(2)`-`t_(2)^(2)`=`K.PN*AB` then `K=`

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