The wave number of the first line in the balmer series of `Be^(3+)` ?

The wave number of the first line is Balmer series of hydrogen in 152000 cm^(-1) . The wave number of the first line in the Balmer series of Li^(2+) is

Wave number of the first line in the Balmer series of Be^(3+) is 2.5×10^(5) cm^(-1) .Wave number of the second line of the Paschen series of Li^(2+) is (A) 7.2×10^(4) cm^(-1) (B) 7.2×10^(5) cm^(-1) (C) 7.2×10^(-4) cm^(-1) (D) 1.8×10^(4) cm^(-1)

The wave number of the first line in the Balmer series of hydrogen is 15200 cm^(-1) . What would be the wavenumber of the first line in the Lyman series of the Be^(3+) ion?

The wave number of the first line in the Balmer series of H-atom is 15200cm^(-1) . Calculate the wave number of the first line in the same series of Li^(2+) ion.

The wave number of the first emission line in the Balmer series of H - Spectrum is (n)/(36)R . The value of 'n' is. (R = Rydberg constant):

The wave number of the first emission line in the Balmer series of H - Spectrum is (n)/(36)R . The value of 'n' is. (R = Rydberg constant):

If the wave number of the first line in the Balmer series of hydrogen atom is 1500cm^(-1) , the wave number of the first line of the Balmer series of Li^(2+) is

The wave number of first line in Balmer series of Hydrogen is 15,200cm^(-1) the wave number of first line in Balmer series of Be^(3+)