Equivalent conductivity of `BaCl_2,H_2SO_4` and HCl, are `x_1,x_2"and"x_3Scm^(-1)eq^(-1)` at infinite dilution. If conductivity of saturated `BaSo_4` solution is x`Scm^(-1)`, then `K_(sp)` of `BaSO_4` is :

Equivalent condictance of BaCI_(2), H_(2)SO_(4) and HCI are x_(1) , x_(2) and x_(3) S cm^(2) "equiv"^(-1) at infinite dilution , if specific condictance of structured BaSO_(4) solution is of y S cm^(-1) then K_(p) of BaSO_(4) is

If equivalent conductivity of BaSO_(4) solution be "x ohm"^(-1)."cm"^(-1)."g-equiv"^(-1) , then calculate its molar conductivity.

Molar conductivities of BaCl_(2), H_(2)SO_(4) and HCl at infinite dilution are x_(1) and x_(2), and x_(3) respectively. Molar conductivity of BaSO_(4) at infinite dilution will be

The equivalent conductance of Ba^(2+) and Cl^(-) are 76ohm^(-1) cm^(2) eq^(-1) and 63.5 ohm^(-1) cm^(2)eq^(-1) , respectively, at infinite dilution . The equivalent conductance ( in ohm^(-1) cm^(2)eq^(-1)) of BaCl_(2) at infinite dilution will be

The equivalent conductance of Ba^(2+) and Cl^(c-) are 63.5ohm^(-1) cm^(2) eq^(-1) and 76 ohm^(-1) cm^(2)eq^(-1) , respectively, at infinite dilution . The equivalent conductance ( in oh^(-1) cm^(2)) of BaCl_(2) at infinite dilution will be

The equivalent conductance of Ba^(2+) and Cl^(c-) are 63.5ohm^(-1) cm^(2) eq^(-1) and 76 ohm^(-1) cm^(2)eq^(-1) , respectively, at infinite dilution . The equivalent conductance ( in oh^(-1) cm^(2)) of BaCl_(2) at infinite dilution will be