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The perpendicular from A on side BC of a...

The perpendicular from A on side BC of a ABC intersects BC at D such that DB = 3 CD. Prove that `2AB^2 = 2AC^2 + BC^2`.

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In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
In `∆ABC` , `AD ⊥ BC` and `BD = 3(CD)`
`=>BD + CD = BC`
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