A body is thrown up in a lift with a velocity `u` relative to the lift, and returns to the lift in time `t`. Show that the lift`s upward acceleration is `(2u-gt)/(t)`.

A body is thrown up in a lift with a velocity 5ms^(-1) relative to the lift and the time of flight is found to be 0.8 s. The acceleration with which the lift is moving up is (g=10ms^(-2))

A body is thrown up in a lift with a velocity 5ms^(-1) relative to the lift and the time of flight is found to be 0.8 s. The acceleration with which the lift is moving up is (g=10ms^(-2))

When a body is thrown up in a lift with a velocity u relative to the lift, the time of flight is found to be t . The acceleration with which the lift is moving up is

When a body is thrown up in a lift with a velocity u relative to the lift, the time of flight is found to be t . The acceleration with which the lift is moving up is

A lift is moving up with a constant acceleration a. A man standing on the lift, throws a ball vertically upwards with a velocity v, which returns to the thrower after a time t. show that v=(a+g) t/2 where g is the acceleration due to gravity.

A coin is dropped in a lift. It takes time t_1 to reach the floor when the lift is stationary. It takes time t_2 when the lift is moving up with constant acceleration, then how t_1 and t_2 are related ?