A force act on a `30 gm` partical as a friction of the partical as a function as given by `x = 3 t - 4 t^(2) + t^(3)`, where `x` is in metros and `t` is in seconds. The work done during the first `4` second is

A force act on a 30 gm particle in such a way that the position of the particle as a function of time is given by x = 3 t - 4 t^(2) + t^(3) , where x is in metros and t is in seconds. The work done during the first 4 second is

A force acts on a 3.0 gm particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where xx is in metres and t is in seconds. The work done during the first 4 seconds is

A force acts on a 3.0 gm particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where xx is in metres and t is in seconds. The work done during the first 4 seconds is

A foce acts on a 30.g particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where x is in metre and t in second. The work done during the first 4s is

A foce acts on a 30g particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where x is in metre and t in second. The work done during the first 4s is

The position of a Particle of Mass 4 g,acted upon by a constant force is given by x= 4t^(2) +t,where x is in metre and t in second .The work done during the first 2 seconds is