In Fig. initialy the system is at rest .Find out minimum value of `F `for which sliding start between the two blocks Given`m_(A) = 10 kg` and `m_(B) = 20 kg`

Initially the system is at rest. find out minimum value of F for which sliding starts between the two blocks.

Initially, both the blocks are at rest on horizontal surface as shown in the figure. Find the minimum value of force F in (N) so that sliding starts between the blocks (g=10ms^(-2))

Initially, both the blocks are at rest on horizontal surface as shown in the figure. Find the minimum value of force F in (N) so that sliding starts between the blocks (g=10ms^(-2))

Find the acceleration of the two blocks The system initally at rest and the friction coefficient are as shown in fig 7.140? Also find maximum F for which two blocks will move togather Given m_(A) = 10 kg and m_(B) = 20 kg

Find the acceleration of the two blocks The system initally at rest and the friction coefficient are as shown in fig 7.140? Also find maximum F for which two blocks will move togather Given m_(A) = 10 kg and m_(B) = 20 kg

The coefficient of friction between block A of mass m_(1)=5kg and block B of mass m_(2)=10 kg is mu_(2)=0.5 . There is no friction froce between block B and fixed horizontal surface. A force of 300N acts on block B in horizontal direction and a horizontal force of magnitude F acts on block A as shown , both towards right. Initially there is no relative motion between the blocks. The minimum value of F such that relative motion starts between A and B is :

The coefficient of friction between block A of mass m_(1)=5kg and block B of mass m_(2)=10 kg is mu_(2)=0.5 . There is no friction froce between block B and fixed horizontal surface. A force of 300N acts on block B in horizontal direction and a horizontal force of magnitude F acts on block A as shown , both towards right. Initially there is no relative motion between the blocks. The minimum value of F such that relative motion starts between A and B is :

In the arrangement shown in figure pulley P can move whereas other two pulleys are fixed. All of them are light. String is light and inextensible. The coefficient of friction between 2 kg and 3 kg block is mu = 0.75 and that between 3 kg block and the table is mu = 0.5 . The system is released from rest (i) Find maximum value of mass M, so that the system does not move. Find friction force between 2 kg and 3 kg blocks in this case. (ii) If M = 4 kg, find the tension in the string attached to 2 kg block. (iii) If M = 4 kg and mu_(1) = 0.9 , find friction force between the two blocks, and acceleration of M. (iv) Find acceleration of M if m_(1) = 0.75, m_(2) = -0.9 and M = 4 kg.

A plank of mass 10kg rests on a smooth horizontal surface. Two blocks A and B of masses m_(A)=2kg and m_(B)=1kg lies at a distance of 3m on the plank as shown in the distance of 3m on the plank as shown in the figure. The friction coefficient between the blocks and plank are mu_(A)=0.3 and mu_(B)=0.1 . Now a force F = 15 N is applied to the plank in horizontal direction. Find the time after which block A collides with B.