The enthalpy change for the following reaction is 368 kJ. Calculate the average O-F bond energy.
`OF_(2)(g)rarrO(g)+2F(g)`

The enthalpy change for the following reaction is 368kJ. Calculate the average O-F bond energy. OF_(2(g)) rarr O_((g)) + 2F_((g))

The net enthalpy change of a reaction is the amount of energy required to break all the bonds in reactant molecules minus amount of energy required to form all the bonds in the product molecules. What will be the enthalpy change for the following reaction ? H_(2) (g) + Br_(2) (g) rarr 2HBr (g) . Given that, bond energy of H_(2), Br_(2) and HBr is 435 kJ mol^(-1), 192 kJ mol^(-1) and 368 kJ mol^(-1) respectively

The net enthalpy change of a reaction is the amount of energy required to break all the bonds in reactant molecules minus amount of energy required to form all the bonds in the product molecules.What will be the enthalpy change for the following reaction. H_(2)(g) + Br_(2)(g) to 2HBr(g) Given that bond energy of H_(2), Br_(2) and HBr is 435 kJ mol^(-1) , 192 kJ mol^(-1) and 368 kJ mol^(-1) respectively.

The enthalpy change for the reaction, C_(2)H_(6)(g)rarr2C(g)+6H(g) is X kJ. The bond energy of C-H bond is :

The enthalpy change for the reaction, C_(2)H_(6)(g)rarr2C(g)+6H(g) is X kJ. The bond energy of C-H bond is :

The enthalpy change for the reaction, C_(2)H_(6)(g)rarr2C(g)+6H(g) is X kJ. The bond energy of C-H bond is :