In the circuit shown , the batteries have emf `E_1 = E_2= 1V , E_3 = 2.5 V,` and the resistance `R_1 = 10Omega, R_2 = 20 Omega`, Capacitance `C = 10 muF`. The charge on the left plate of the charge on the left plate of the capacitor C at steady state is

In Fig, E =5 volt , r = 1 Omega, R_(2) = 4 Omega, R_(1) = R_(3) = 1 Omega and C = 3 muF . Then the numbercal value of the charge on each plate of the capacitor is

In Fig, E =5 volt , r = 1 Omega, R_(2) = 4 Omega, R_(1) = R_(3) = 1 Omega and C = 3 muF . Then the numbercal value of the charge on each plate of the capacitor is

Find a potential difference varphi_(A) - varphi_(B) between the plates of a capacitor C in the circuit shown in Fig, if the sources have emf's E_(1) = 40 V, E_(2) = 1.0 V and the resistances are equal to R_(1) = 10 Omega, R_(2) = 20 Omega , and R_(3) = 30 Omega . The internal resistances of the sources are negligble.

In the circuit shown in fig. R_(1) = 10 Omega, R_(2) = 5 Omega, C_(1) = 1 muF, C_(2) = 2muF, and E =6V. Calculate the charge on each capactor in the stedy state.

In the circuit shown in fig. R_(1) = 10 Omega, R_(2) = Omega, C_(1) = 1 muF, C_(2) = 2muF, and E =6V. Calculate the charge on each capactor in the stedy state.

A circuit consists of three batteries of emf E_1 = 1 V, E_2 = 2 V and E_3 = 3 V and internal resistances 1Omega, 2 Omega and 1 Omega respectively which are connected in parallel as shown in the figure. The potential difference between points P and Q is

In the given circuit, R_(1) = 10Omega R_(2) = 6Omega and E = 10V, then correct statement is

In the given circuit, R_(1) = 10Omega R_(2) = 6Omega and E = 10V, then correct statement is