Light quanta with energy 4.9 eV eject photoelectrons from metal with work function 4.5 eV. Find the maximum impulse transmitted to the surface of the metal when each electron flies out.

The energy of emitted photoelectrons from a metal is 0.9ev , The work function of the metal is 2.2eV . Then the energy of the incident photon is

Two photons, each of energy 2.5eV are simultaneously incident on the metal surface. If the work function of the metal is 4.5eV then from the surface of the metal.

Work function of a metal is 4.0 eV. Find the maximum value of wavelength of a radiation that can emit photoelectrons from the metal.

Two photons, each of energy 2.5 eV are simultaneously incident on the metal surface. If the work function of the metal is 4.5 eV, then from the surface of metal

Radiation of a certain wavelength causes electrons with a maximum kinetic energy of 0.65 eV to be ejected from a metal surface whose work function is 2.65 eV. What will be the maximum kinetic energy (in eV) with which this same radiation ejects electrons from another metal whose work function is 2.15eV.

Light of wavelength 2000Å is incident on a metal surface of work function 3.0 eV. Find the minimum and maximum kinetic energy of the photoelectrons.

Light of wavelength 2000Å is incident on a metal surface of work function 3.0 eV. Find the minimum and maximum kinetic energy of the photoelectrons.

Two radiation of photons energy 3eV and 4.5 eV successively illuminate a photosensitive metallic surface of work function 2.5 eV the ratio of the maximum speeds of the emitted electrons is :-

The light photons of energy 1.5 eV and 2.5 eV are incident on a metallic surface of work function 0.5 eV, the ratio of the maximum kinetic energy of the photoelectrons is

Photons of energy 3.55 eV each are incident on a metal surface whose work function is 1.9 eV. What is the maximum K.E with which an electron is ejected form tis surface ?