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ABC is an isosceles triangle right-angl...

ABC is an isosceles triangle right-angled at C. Prove that `A B^2=2A C^2`.

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In `ΔABC, ∠ACB = 90°` and `AC = BC` [Since, ABC is an isosceles triangle right angled at C]
Using Pythagoras theorem,
`⇒( AB)^2 = (AC)^2 + (BC)^2`
`⇒ (AB)^2 = (AC)^2 + (AC)^2 ` [Since AC = BC] ...
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