Velocity of particle of mass 2kg varies with time t accoridng to the equation `vecv=(2thati+4hatj)ms^(-1)`. Here t is in seconds. Find the impulse imparted to the particle in the time interval from t=0 to t=2s.

Explanation

Impulse=Change in momentum`=m(vecv_(2)-vecv_(1))`
`=2xx[(4hati+4hatj)-(4hatj)]=8hati kgms^(-1)`