In the arrangement shows in fig. if the surface is smooth then find out acceleration of the block `m_(2)`.

Explanation

Let accelration of `m_(2)` be a then acceleration of `m_(1)` will be `2a`.
for `m_(1):T=m_(1)(2a)` and for `m_(2):m_(2)g-2T=m_(2)a`
`rArrm_(2)g-4m_(1)a=m_(2)arArra=(m_(2)g)/(4m_(1)+m_(2))`