The monkey B shown in fig. is holding on to the tall of the monkey A which is climbing up a rope. The masses of the monkeys A and B are 5 kg and 2kg respectively. If A can tolerate a tension of 30N in its tall, what force should it apply on the rope in order to carry the monkey B with it ?
(Take `g=10 ms^(-2)`)

Explanation

`T_("min")=(5+2)g=7g=70N`
Suppose maximum permissible acceleration of system is `a_("max")` then equation of motion of or lower monkey
`T_(1)-2g=2a_("max")rArrT_(1)=2g+2a_("max")`
given `T_(1)=30N`
`2g+2a_("max")=30`
`a_("max")=5m//s^(2)`
`therefore` for system `T=(502)(10+5)=105N`