The friction coefficient between the board and the floor shown in figure is `mu` Find the maximum force that the man can exert on the rope so that the board does not slip on the floor

Explanation

`N+T=(N+m)g`
`N=(M+m)g-T`
Condition of man for no slipping to be occur is
`T=f_(r)rArrT=muNrArrT=mu(M+m)g-T)`
`rArrT(1+mu)=mu(M+m)grArrT=(mu(M+m)g)/((1+mu))`