A block of mass 1kg lies on a horizontal surface in a turck, the coefficient of static fricition between the block and the surface is 0.6, what is the force of fricition on the block. If the acceleration of the truck is `5m//s^(2)`.

Explanation

Fictitious force on the block `F=ma=1xx5=5N`
While the limiting friction force
`F=mu_(s)N=mu_(s)mg=0.6xx1xx9.8=5.88N`
As applied force F lesser than limiting friciton force. The block will remain at rest in the truck and the force of friction will be equal to 5N and in the direction of accelration of the truck.