A block has been placed on an inclined p...

A block has been placed on an inclined plane . The slope angle of `theta` of the plane is such that the block slides down the plane at a constant speed . The coefficient of kinetic friction is equal to :

`sin theta`

`cos theta`

`tan theta`

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The correct Answer is:

When the block slides down the plane with a constant speed then the inclination of the plane is equal to angle of repose `(theta)`.
Coefficient of friction=tan of the angle of reposed `=tan theta`.

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