Two weights `w_(1)` and `w_(2)` are suspended from the ends of a light string passing over a smooth fixed pulley. If the pulley is pulled up at an acceleration g , the tension in the string will be

Options

A. `(2w_(1)w_(2))/(w_(1)+w_(2))`
B. `(w_(1)w_(2))/(w_(1)+w_(2))`
C. `(4w_(!)w_(2))/(w_(1)+w_(2))`
D. `(4w_(1)w_(2))/(w_(1)-w_(2))`

Answer

C

Explanation

From pully frame pseudo fore equal to weight acts on bodies respectively.
`2w_(2)-T=(w_(2))/(g)=a`
`T=2w_(1)=(Gw_(1)w_(2))/((w_(1)+w_(2)))`
Solving `T=(Gw_(1)w_(2))/((w_(1)+w_(2))`