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A rocket of mass 1000 kg is to be projec...

A rocket of mass 1000 kg is to be projected vertically upwards. The gases are exhausted vertically downwards with velocity `100m//s` with respect to the rocket. (What is the minimum rate of burning fuel, so as to just lift the rocket upwards against the gravitational attraction?) (Take `g=10m//s^(2)`)

A

50 kg/s

B

100kg/s

C

200kg/s

D

400kg/s

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the minimum rate of burning fuel for the rocket to just lift off against gravitational attraction, we can follow these steps: ### Step 1: Understand the Forces Acting on the Rocket The rocket must generate enough thrust to overcome the gravitational force acting on it. The gravitational force \( F_g \) can be calculated using the formula: \[ F_g = m \cdot g \] where: - \( m \) is the mass of the rocket (1000 kg) - \( g \) is the acceleration due to gravity (10 m/s²) ### Step 2: Calculate the Gravitational Force Substituting the values into the formula: \[ F_g = 1000 \, \text{kg} \cdot 10 \, \text{m/s}^2 = 10000 \, \text{N} \] This means the rocket needs to exert a thrust of at least 10000 N to just lift off. ### Step 3: Relate Thrust to Mass Flow Rate The thrust \( F \) produced by the rocket can also be expressed in terms of the mass flow rate \( \frac{dm}{dt} \) and the exhaust velocity \( v_e \): \[ F = \frac{dm}{dt} \cdot v_e \] where: - \( v_e \) is the velocity of the exhaust gases (100 m/s) ### Step 4: Set Up the Equation for Thrust To find the minimum rate of burning fuel, we set the thrust equal to the gravitational force: \[ \frac{dm}{dt} \cdot v_e = F_g \] Substituting the known values: \[ \frac{dm}{dt} \cdot 100 \, \text{m/s} = 10000 \, \text{N} \] ### Step 5: Solve for the Mass Flow Rate Now, we can solve for \( \frac{dm}{dt} \): \[ \frac{dm}{dt} = \frac{10000 \, \text{N}}{100 \, \text{m/s}} = 100 \, \text{kg/s} \] ### Conclusion The minimum rate of burning fuel required for the rocket to just lift off is: \[ \frac{dm}{dt} = 100 \, \text{kg/s} \] ### Final Answer Thus, the answer is **100 kg/s**. ---

To solve the problem of determining the minimum rate of burning fuel for the rocket to just lift off against gravitational attraction, we can follow these steps: ### Step 1: Understand the Forces Acting on the Rocket The rocket must generate enough thrust to overcome the gravitational force acting on it. The gravitational force \( F_g \) can be calculated using the formula: \[ F_g = m \cdot g \] where: ...
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