A 5kg. mass is accelerated from rest to 60 m/s in 1 sec. what force acts on it:-

Options

A. `5xx60N`
B. `(5//60)xx981N`
C. `60^(2)xx52N`
D. `(5/2)xx60^(2)xx981N`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify the given values
- Mass (m) = 5 kg
- Initial velocity (u) = 0 m/s (since the mass starts from rest)
- Final velocity (v) = 60 m/s
- Time (t) = 1 s

### Step 2: Calculate the acceleration
We can use the formula for acceleration (a):
\[ a = \frac{v - u}{t} \]
Substituting the values:
\[ a = \frac{60 \, \text{m/s} - 0 \, \text{m/s}}{1 \, \text{s}} = \frac{60 \, \text{m/s}}{1 \, \text{s}} = 60 \, \text{m/s}^2 \]

### Step 3: Calculate the force acting on the mass
Using Newton's second law of motion, the force (F) can be calculated using the formula:
\[ F = m \cdot a \]
Substituting the values:
\[ F = 5 \, \text{kg} \cdot 60 \, \text{m/s}^2 = 300 \, \text{N} \]

### Step 4: State the final answer
The force acting on the mass is:
\[ \text{Force} = 300 \, \text{N} \]