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Three blocks are connected as shown in fig. on a horizontal frictionless table if `m_(1)=1 kg, m_(2)=8kg, m_(3)=27kg` and `T_(3)=36N, T_(2)` will be:-

A

18N

B

9N

C

3.375N

D

1.75N

Text Solution

Verified by Experts

The correct Answer is:
B

`a=(36)/(36)=1m//s^(2)`
`T_(3)-T_(2)=M_(3)a`
`therefore T_(2)=36-27xx1=9N`
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