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A ball weighing 10g hits a hard surface ...

A ball weighing `10g` hits a hard surface vertically with a speed of `5m//s` and rebounds with the same speed The ball remains in contact with the surface speed The ball remains in contact with the surface for `0.01s` The average force exerted by the surface on the ball is .

A

100N

B

10N,16N

C

1N

D

0.1N

Text Solution

Verified by Experts

The correct Answer is:
B
`F_("avg")=(2xx(10)/(1000)xx5)/(0.01)=10N`
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