A body of mass `10kg` is moving with a constant velocity of `10m//s`. When a constant force acts for 4 seconds on it, it moves with a velocity `2m//sec` in the opposite direction. The acceleration produced in it is

Options

A. `3 m//s^(2)`
B. `-3m//s^(2)`
C. `0.3 m//s^(2)`
D. `-0.3 m//s^(2)`

Answer

B

Explanation

`a=(-2-10)/(4)=(-12)/(4)=-3m//s^(2)`