A block of mass 2 kg is placed on the fl...

A block of mass 2 kg is placed on the floor . The coefficient of static friction is `0.4` . If a force of `2.8` N is applied on the block parallel to floor , the force of friction between the block and floor is : (Taking g = `10 m//s^(2)`)

2.8N

2.0N

zero

Text Solution

Verified by Experts

The correct Answer is:

`f_("max")=20xx0.4=8N`
`therefore f=2.8N`

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