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A car is moving along a straight horizontal road with a speed `v_(0)` . If the coefficient of friction between the tyres and the road is `mu` , the shortest distance in which the car can be stopped is

A

`(V_(0)^(2))/(2mug)`

B

`(V_(0)^(2))/(mug)`

C

`((V_(0))/(mug))^(2)`

D

`(2V_(0)^(2))/(mug)`

Text Solution

Verified by Experts

The correct Answer is:
A
`O^(2)-V_(0)^(2)=2(-mug)xxs`
`s=(V_(0)^(2))/(2mug)`
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