The rear side of a truck is open and a box of mass `20kg` is placed on the truck `4m` away from the open end `mu = 0.15` and `g = 10m//s^(2)` The truck starts from rest with an acceleration of `2m//s^(2)` on a straight road The box will fall off the truck when it is at a distance from the starting point equal to .

Options

A. 4m
B. 8m
C. 16m
D. 32m

Answer

C

Explanation

`a_(r)=(20xx2-20xx10xx0.5)/(20)=0.5m//s^(2)`
`therefore 4=(1)/(2)xx0.5xxt^(2) t=4s`
`therefore` distance of truck `=(1)/(2)xx2xx4xx4=16m`