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The coefficient of friction between a bo...

The coefficient of friction between a body and the surface of an inclined plane at `45^(@)` is 0.5. if `g=9.8m//s^(2)`, the acceleration of the body downwards I `m//s^(2)` is

A

`(4.9)/sqrt(2)`

B

`4.9sqrt(2)`

C

`19.6sqrt(2)`

D

`4.9`

Text Solution

Verified by Experts

The correct Answer is:
A
`a=g sin theta-mug cos theta`
`g((1)/sqrt(2)-0.5xx(1)/sqrt(2))=(9.8xx0.5)/sqrt(2)=(4.9)/sqrt(2)`
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ALLEN-NEWTONS LAWS OF MOTION-EXERCISE-II
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