A trolley of mass 5 kg on a horizontal smooth surface is pulled by a load of mass 2 kg by means of uniform rope ABC of length 2 m and mass 1kg. As the load falls from BC=0 to BC=2m. Its accerleration in `m//s^(2)` change-

Options

A. `(20)/(6)` to `(20)/(5)`
B. `(20)/(8)` to `(30)/(8)`
C. `(20)/(5)` to `(30)/(6)`
D. None of the above

Answer

B

Explanation

For `BC=0, a=(2g)/(2+5+1)=(g)/(4)=(10)/(4)=(20)/(8)ms^(-2)`
For `BC=2m, a=((2+1)g)/(2+5+1)=(3g)/(8)=(30)/(8)ms^(-2)`