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One end of a brass rod 2m long and havin...

One end of a brass rod `2m` long and having `1cm` radius is maintained at `250^(@)C`. When a steady state is reached , the rate of heat flow acrss any cross-section is `0.5 cal s^(-1)`. What is the temperature of the other end `K=0.26"cal" s^(-1) cm^(-1). ^(@)C^(-1)`.

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AI Generated Solution

To solve the problem step-by-step, we will use the formula for heat conduction through a rod, which is given by Fourier's law of heat conduction. The formula can be expressed as: \[ Q = k \cdot A \cdot \frac{(T_1 - T_2)}{L} \] Where: - \( Q \) is the rate of heat flow (in cal/s), ...
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