At what temperature , will the root mean square velocity on hydrogen be double of its value at `S.T.P`., pressure remaining constant ?

Explanation

Let `v_(1)` be the `r.m.s` velocity at `S.T.P.(=273K`) and `v_(2)` be the `r.m.s` velocity at unknown temperature `T_(2)`.
`therefore (v_(1)^(2))/(v_(2)^(2)) = (T_(1))/(T_(2))`
or `T_(2) =T_(1)[v_(2)/v_(1)]^(2) = 273xx(2)^(2) = 273xx4`
`=1092 K = (1092-273) = 819^(@)C`