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Calculate the difference between the two...

Calculate the difference between the two principal specific heats of 1g of helium gas at S.T.P. Given atomic weight of helium = 4 and `J = 4.186 J cal^(-1)` and `R = 8.31 J mol^(-1)K^(-1)`.

Text Solution

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Gas constant for `1` g of helium , r= `(R)/(M_(w)) = (PV)/(TxxM_(w)) = (76xx13.6xx981xx22400)/(273xx4) = 2.08 xx10^(7) "erg" g^(-1) K^(-1)`
`C_(P) -C_(V) = (r)/(J) = (2.08xx10^(7))/(4.186xx10^(7)) = 0.5"cal" g^(-1) K^(-1)`
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