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A Carnot engine works as a refrigerator ...

A Carnot engine works as a refrigerator in between `250K` and `300K`. If it acquires `750` calories form heat source at low temperature, then what is the heat generated at higher temperature (in calories)?

Text Solution

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` T_(1) = 300 K " " T_(2) = 250K " " Q_(2) = 750 " " Q_(1)=?`
`(Q_(1))/(Q_(2)) = (T_(1))/(T_(2)) " " Q_(1) = (300)/(250) xx 750 = 900 "cal"`
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