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In Newton's law of cooling (d theta)/(dt...

In Newton's law of cooling `(d theta)/(dt)=-k(theta-theta_(0))` the constant `k` is proportional to .

A

`A`, surface area of the body

B

`S`, specific heat of the body

C

`(1)/(m)`, m being mass of the body

D

e, emissity of the body

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The correct Answer is:
A, C
`(dQ)/(dt) = esigmaA(theta^(4)-theta_(0)^(4)) approx(3esigmaAtheta_(0)^(3))Deltatheta`
`(dQ)/(dt) = esigmaA(theta^(4)-theta_(0)^(4)) approx(3esigmaAtheta_(0)^(3))Deltatheta`
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