A clock pendulum made of invar has a period of `2` s at `20^(@)C`. If the clock is used in a climate where average temperature is `40^(@)C`, what correction (in seconds ) may be necessary at the end of `10` days to the time given by clock? `(alpha_("invar") = 7 xx 10^(-7) "^(@)C, 1` "day" =`8.64xx10^(4)s`)

Answer

6

Explanation

`T=2pisqrt((l)/(g)) implies (DeltaT)/(T) = (1)/(2) (Deltal)/(l) (1)/(2)(alphaDeltatheta) implies DeltaT = (T)/(2)(alphaDeltatheta)= ((10xx8.64 xx 10^(4))/(2)) (7xx10^(-7)) (20) = 6s`